# Example 28 - Linear Regression. Pressure Data.
# Verified Solution: a0 = 8.75201, a1 = 2035.33
# Ref.: Comput. Appl. Eng. Educ. 6: 173, 1998
[
TC P
-36.7 1
-19.6 5
-11.5 10
-2.6 20
7.6 40
15.4 60
26.1 100
42.2 200
60.6 400
80.1 760
]
logP=log(P)
TK=TC+273.15
neginvTK = -1/TK
mlinfit neginvTK logP
logP = a0 + a1neginvTK
| Variable |
Value |
95% confidence |
| a0 |
8.75201 |
0.54233497 |
| a1 |
2035.331 |
153.62831 |
| R^2 |
R^2adj |
Rmsd |
Variance |
| 0.9915016 |
0.9904393 |
0.024644 |
0.0075916 |
Regression Plot

Residuals Plot

Source data points and calculated data points
| |
neginvTK |
logP |
logP calc |
Delta logP |
| 1 |
-0.00422922 |
0 |
0.14413927 |
-0.14413927 |
| 2 |
-0.003944 |
0.69897 |
0.72467403 |
-0.02570403 |
| 3 |
-0.0038219 |
1 |
0.97317937 |
0.02682063 |
| 4 |
-0.00369617 |
1.30103 |
1.2290714 |
0.07195858 |
| 5 |
-0.00356189 |
1.60206 |
1.5023892 |
0.09967078 |
| 6 |
-0.0034656 |
1.7781513 |
1.6983589 |
0.07979239 |
| 7 |
-0.00334169 |
2 |
1.9505696 |
0.04943039 |
| 8 |
-0.00317108 |
2.30103 |
2.297813 |
0.00321704 |
| 9 |
-0.00299625 |
2.60206 |
2.6536399 |
-0.05157986 |
| 10 |
-0.00283086 |
2.8808136 |
2.9902802 |
-0.10946665 |
General
Number of independent variables = 1
Regression including a free parameter
Number of observations = 10